Answer
381.34 Hz
Work Step by Step
Here we use the equation $f^{'}=(\frac{f}{1\space \pm u/V })$ where, $f^{'}$ - shifted frequency, f - original frequency, u - speed of the car, V - speed of the sound wave in the air.
$f^{'}=(\frac{f}{1\space \pm u/V })$
We'll use the minus sign because the source is approaching.
$f^{'}=(\frac{f}{1\space -u/V })$ Let's plug known values into this equation.
$f^{'}=(\frac{352\space s^{-1}}{1\space -(\frac{95km}{h})(\frac{1000m}{km})(\frac{h}{3600s})/343m/s })$
$f^{'}=381.34\space Hz$
