Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 271: 43

Answer

She has to wait for 7.08 s for the next wave.

Work Step by Step

Here we use the equation $V=\sqrt {\frac{\lambda g}{2\pi}}$ to find the speed of the wave. where V - speed of the wave, $\lambda$ - wave length, g - gravitational acceleration. $V=\sqrt {\frac{\lambda g}{2\pi}}$ ; Let's plug known values into this equation. $V=\sqrt {\frac{78.2m\times 9.8m/s^{2}}{2\pi}}=11.04\space m/s$ Let's apply the equation $S=ut$ to find the waiting time of the surfer. where S - displacement of the wave, u - speed of the wave, t - time. $S=ut$ ; Let's plug known values into this equation. $78.2m=11.04\space m/s\times t$ $t=7.08\space s$ She has to wait for 7.08 s for the next wave.
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