Answer
269.39 m/s
Work Step by Step
Here we use the equation $V=\sqrt {\frac{\gamma P}{\rho}}$ , Where V - speed of the sound, $\gamma$ - specific heat ratio of the gas, $\rho $ - density of the gas.
$V=\sqrt {\frac{\gamma P}{\rho}}$ ; Let's plug known values into this equation.
$V=\sqrt {\frac{1.31\times1.95\times10^{4}kgm^{-1}s^{-2}}{0.352\space kg/m^{3}}}=269.39\space m/s$