Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 271: 29

Answer

269.39 m/s

Work Step by Step

Here we use the equation $V=\sqrt {\frac{\gamma P}{\rho}}$ , Where V - speed of the sound, $\gamma$ - specific heat ratio of the gas, $\rho $ - density of the gas. $V=\sqrt {\frac{\gamma P}{\rho}}$ ; Let's plug known values into this equation. $V=\sqrt {\frac{1.31\times1.95\times10^{4}kgm^{-1}s^{-2}}{0.352\space kg/m^{3}}}=269.39\space m/s$
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