Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 208: 48

Answer

$M = 45.2 \ kg$

Work Step by Step

a) We know that angular momentum is conserved. Thus, we find the initial angular momentum. (Recall, we must convert rpm to radians per second.) $L_i = I\omega=(.22)(13.61)=3$ Using the equation for the moment of inertia of a solid cylinder, we find: $6 = (.31+\frac{1}{2}M(.15)^2)(7.33) $ $M = 45.2 \ kg$ *Note, we set this equal to 6 since the angular momentum changes from 3 to -3, which is a change of 6.
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