Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 208: 44

Answer

a) $14.2 \ Js$ b) $57 \ Nm$

Work Step by Step

a) We use the parallel axis theorem to obtain: $I_t = .048 +mR^2 = .048+(.88)(.43)^2 = .21$ Recall that $\omega=\frac{v}{r}$, it follows: $L=I\omega=I\frac{v}{r}=(.021)\frac{50}{.74}=14.2 \ Js$ b) We obtain: $\tau = \frac{L}{t}=\frac{14.2}{.25}=57 \ Nm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.