Essential University Physics: Volume 1 (4th Edition)

We first find the moment of inertia of the dog: $I_{dog}=mR^2 = 17 \times (1.81^2)=55.69$ Using this and calling p the percentage, we find: $p = (1+ \frac{55.7}{95})^{-1}\times 100=\fbox{63 percent}$