Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 208: 47

Answer

63 percent

Work Step by Step

We first find the moment of inertia of the dog: $I_{dog}=mR^2 = 17 \times (1.81^2)=55.69$ Using this and calling p the percentage, we find: $p = (1+ \frac{55.7}{95})^{-1}\times 100=\fbox{63 percent}$
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