Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 11 - Exercises and Problems - Page 208: 45

Answer

.2063

Work Step by Step

We know that the moment of inertia must decrease by 70 percent, so we multiply the current moment of inertia by .7. In addition, we know that the wheel must go down in diameter from .38 to .35, so we multiply by $\frac{.35}{.38}$. Thus, we find: $I_{new}=.32 \times .7 \times \frac{.35}{.38}=\fbox{.2063}$
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