Answer
Therefore the final temperature of the ethanol sample is 20.1$^{\circ}$ C
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
562 = (25.248) (2.44) ($\Delta t $)
***We multiply 25.248 times 2.44 and then divide 562 by that answer
*** solve using a calculator
$ \Delta t = 9.12 ^{\circ} $
Therefore the temperature change is $9.12 ^{\circ}$
The initial temp is 11 so the final temp = initial temp + $ \Delta t$
= 11 + 9.12 = 20.1
Therefore the final temperature is 20.1$^{\circ}$ C
