## Introductory Chemistry (5th Edition)

Therefore the final temperature of the ethanol sample is 20.1$^{\circ}$ C
We will use the equation $q=mc\Delta t$ q = heat transferred m = mass c = specific heat $\Delta t$ = change in temperature plug in the values. 562 = (25.248) (2.44) ($\Delta t$) ***We multiply 25.248 times 2.44 and then divide 562 by that answer *** solve using a calculator $\Delta t = 9.12 ^{\circ}$ Therefore the temperature change is $9.12 ^{\circ}$ The initial temp is 11 so the final temp = initial temp + $\Delta t$ = 11 + 9.12 = 20.1 Therefore the final temperature is 20.1$^{\circ}$ C