Answer
Therefore the specific heat capacity of the metal is 2.2 J/g$^{\circ}$C.
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
56 = (11) (c) (2.3)
***We multiply 11 times 2.3 and then divide 56 by that answer
*** solve using a calculator
c= 2.2
Therefore the specific heat capacity of the metal is 2.2 J/g$^{\circ}$C
