Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Cumulative Problems - Page 90: 82

Answer

Therefore the final temperature is 23.92$^{\circ}$

Work Step by Step

We will use the equation $q=mc\Delta t$ q = heat transferred m = mass c = specific heat $\Delta t $ = change in temperature plug in the values. 345000 = (45000) (4.2) ($\Delta t $) ***We multiply 45000 times 4.2 and then divide 345000 by that answer *** solve using a calculator $ \Delta t = 1.82 ^{\circ} $ Therefore the temperature change is $1.82^{\circ}$ The initial temp is 22.1 so the final temp= initial temp + $ \Delta t$ = 22.1 + 1.82 = 23.92 Therefore the final temperature is 23.92$^{\circ}$
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