Answer
Therefore the specific heat capacity is 0.13 J/g$^{\circ}$C and thus, the metal is gold, as the specific heat capacity of gold is 0.13 J/g$^{\circ}$C.
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
2.8 = (5.6) (c) (3.9)
***We multiply 5.6 times 3.9 and then divide 2.8 by that answer
*** solve using a calculator
c= 0.13
Therefore the specific heat capacity is 0.13 J/g$^{\circ}$C and thus, the metal is gold, as the specific heat capacity of gold is 0.13 J/g$^{\circ}$C