#### Answer

Therefore the heat required is $2.08 \times 10^{4}$ J

#### Work Step by Step

We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
q = (3500) (0.129) (46)
*** solve using a calculator
q= $2.08 \times 10^{4}$ J
Therefore the heat required is $2.08 \times 10^{4}$ J