Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Cumulative Problems - Page 90: 78


Therefore the heat required is $2.08 \times 10^{4}$ J

Work Step by Step

We will use the equation $q=mc\Delta t$ q = heat transferred m = mass c = specific heat $\Delta t $ = change in temperature plug in the values. q = (3500) (0.129) (46) *** solve using a calculator q= $2.08 \times 10^{4}$ J Therefore the heat required is $2.08 \times 10^{4}$ J
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