## Introductory Chemistry (5th Edition)

Therefore the heat required is $2.08 \times 10^{4}$ J
We will use the equation $q=mc\Delta t$ q = heat transferred m = mass c = specific heat $\Delta t$ = change in temperature plug in the values. q = (3500) (0.129) (46) *** solve using a calculator q= $2.08 \times 10^{4}$ J Therefore the heat required is $2.08 \times 10^{4}$ J