General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 9 - Solutions - Additional Questions and Problems - Page 366: 9.114

Answer

0.763 M KCl solution.

Work Step by Step

- Calculate or find the molar mass for $ KCl $: $ KCl $ : ( 35.45 $\times$ 1 )+ ( 39.10 $\times$ 1 )= 74.55 g/mol - Using the molar mass as a conversion factor, find the amount in moles: $$ 15.6 \space g \times \frac{1 \space mole}{ 74.55 \space g} = 0.209 \space mole$$ $1 \space L = 1000 \space mL$ $$Volume(L) = 274 \space mL \times \frac{1 \space L}{1000 \space mL} = 0.274 \space L$$ - Write the molarity expression and evaluate it: $$Molarity(M) = \frac{moles \space of \space solute}{liters \space of \space solution}$$ $$= \frac{0.209 \space mole \space KCl}{ 0.274 \space L \space solution} = 0.763 \space M \space KCl \space solution$$
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