Answer
1.5 L of this glucose solution.
Work Step by Step
$5.0\%$ (m/v) $ C_6H_{12}O_6 $ solution : $$ 5.0 \space g \space C_6H_{12}O_6 = 100 \space mL \space solution$$
$$75 \space g \space C_6H_{12}O_6 \times \frac{100 \space mL \space solution}{5.0 \space g \space C_6H_{12}O_6} \times \frac{1 \space L}{1000 \space mL}= 1.5 \space L \space solution$$
