Answer
a. This forms an unsaturated solution.
b. This forms a saturated solution.
c. This forms a saturated solution.
Work Step by Step
1. Calculate the mass of $KCl$ per 100 g of water in each case.
a. $$100 \space g \space H_2O \times \frac{25 \space g \space KCl}{100. \space g \space H_2O} = 25 \space g \space KCl$$
b. $$100 \space g \space H_2O \times \frac{15 \space g \space KCl}{25 \space g \space H_2O} = 60 \space g \space KCl$$
c. $$100 \space g \space H_2O \times \frac{86 \space g \space KCl}{150. \space g \space H_2O} = 57 \space g \space KCl$$
2. If this amount is equal or greater than 43 g, the solubility per 100 g of water, the solution is saturated. If it is not, the solution is unsaturated.
a. 25 g < 43 g: Unsaturated solution.
b. 60 g > 43 g: Saturated solution.
c. 57 g > 43 g: Saturated solution.
