## General Chemistry (4th Edition)

Published by University Science Books

# Chapter 4 Early Quantum Theory - Problems - Page 133: 35

#### Answer

$0.106\cdot 10^{-34}m$

#### Work Step by Step

$\lambda=\dfrac{h}{mv}=\dfrac{6.63\cdot 10^{-34}m^2kgs^{-1}}{75kg\cdot0.833ms^{-1}}=0.106\cdot 10^{-34}m$

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