General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 4 Early Quantum Theory - Problems: 34

Answer

$v=0.0075\cdot 10^{9}\text{ms}^{-1}$

Work Step by Step

$$v=\dfrac{h}{m\lambda}=\dfrac{6.63\cdot 10^{-34}\text{Js}}{9.1\cdot 10^{-31}\text{kg}\cdot96\cdot 10^{-12}\text{m}}=0.0075\cdot 10^{9}\text{ms}^{-1}$$
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