General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 4 Early Quantum Theory - Problems - Page 133: 32


$\lambda=0.00237\cdot 10^{-31}\text{m}$

Work Step by Step

$$\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34}\text{Js}}{5\cdot 10^{-3}\text{kg}\cdot 558.8\frac{m}{s}}=0.00237\cdot 10^{-31}\text{m}$$
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