General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 4 Early Quantum Theory - Problems: 31

Answer

$3.97\cdot 10^{-12}\text{m}$

Work Step by Step

$\lambda=\dfrac{h}{p}=\dfrac{6.63\cdot 10^{-34}\text{Js}}{10^5\text{m} \text{s}^{-1} \cdot 1.67\cdot 10^{-27}\text{kg}}=3.97\cdot 10^{-12}\text{m}$
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