General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 4 Early Quantum Theory - Problems: 36

Answer

$0.663\cdot 10^{-19}kg$

Work Step by Step

$m=\dfrac{h}{v\lambda}=\dfrac{6.63\cdot 10^{-34}m^2kgs^{-1}}{100ms^{-1}\cdot 0.1\cdot 10^{-15}m}=0.663\cdot 10^{-19}kg$
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