General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 14 Thermochemistry - Problems - Page 509: 3

Answer

82500 J

Work Step by Step

$w=-P\Delta V=-(110.0\times10^{3}\,Pa)(0.75\,m^{3})$ $=-82500\,J$ Negative sign indicates that the work is done by the system and can be neglected. Work done by the gas is 82500 J.
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