Answer
3.2 kJ
Work Step by Step
We find:
w=$ -p_{ex}∆V$= -4.0 atm×(2.0-10.0)L
=(-4.0 atm)(-8.0L)= 32. L.atm
32. L.atm= $32. L.atm\times\frac{101.33J}{1L.atm}$ ( As 1 L.atm= 101.33 J)
= $3.2×10^{3}J$
General Chemistry (4th Edition)
by McQuarrie, Donald A.
Published by
University Science Books
ISBN 10:
1891389602
ISBN 13:
978-1-89138-960-3
Chapter 14 Thermochemistry - Problems - Page 509: 2
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