Answer
3.2 kJ
Work Step by Step
We find:
w=$ -p_{ex}∆V$= -4.0 atm×(2.0-10.0)L
=(-4.0 atm)(-8.0L)= 32. L.atm
32. L.atm= $32. L.atm\times\frac{101.33J}{1L.atm}$ ( As 1 L.atm= 101.33 J)
= $3.2×10^{3}J$
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