General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 14 Thermochemistry - Problems - Page 509: 2

Answer

3.2 kJ

Work Step by Step

We find: w=$ -p_{ex}∆V$= -4.0 atm×(2.0-10.0)L =(-4.0 atm)(-8.0L)= 32. L.atm 32. L.atm= $32. L.atm\times\frac{101.33J}{1L.atm}$ ( As 1 L.atm= 101.33 J) = $3.2×10^{3}J$
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