General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 14 Thermochemistry - Problems - Page 509: 1

Answer

5300 J

Work Step by Step

$w=-P\Delta V=-(3.5\,atm)(25\,L-10\,L)$ $=-52.5\,L\cdot atm=-52.5\,L\cdot atm\times\frac{101.325\,J}{1\,L\cdot atm}$ $=-5300\,J$ Negative sign indicates that the work is done by the system. Work done by the system is 5300 J.
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