Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises: 5.53a

Answer

$2.664J$

Work Step by Step

1. Calculate $\Delta T$: $\Delta T = T_F - T_I$ $\Delta T = 25 - 10 = 15^ºC$ 2. Using the specific heat formula: $s = \frac{q}{m \times \Delta T}$ $2.22 = \frac{q}{80 \times 15}$ $2.22 = \frac{q}{1200}$ $2.22 \times 1200 = q$ $q = 2664J$
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