Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises: 5.44c


10.39 grams

Work Step by Step

From the balanced reaction we have that 2 moles of CH3OH produces 2 moles of CH4 and an enthalpy change of 252.8 kJ. Given that we have an enthalpy change of 82.1 kJ, we can use the ratio from the balanced reaction to find how many moles of methane are produced: 82.1 kJ * (2 moles CH4/ 252.8 kJ) = 0.6495 moles CH4 To find how many grams, we need to ind the molar mass of methane; C has a mass of 12 g/mol H has a mass of 1 g/mol, 4 * 1 = 4 CH4 has a mass of 16 g/mol Since we have 0.6495 mole * (16 g /1 mole) = 10.39 grams
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