Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 206: 5.45a

Answer

-29.475 kJ

Work Step by Step

Given Ag+ + Cl- --> AgCl $\Delta H = -65.5 kJ $, it means that for each mole of AgCl formed, 65.5 kJ of heat are released. To find $\Delta H$ for the production of 0.450 mol, it would be 0.450 * -65.5 kJ = -29.475 kJ

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