## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 5 - Thermochemistry - Exercises - Page 206: 5.47a

#### Answer

$\Delta H = + 726.5 kJ$

#### Work Step by Step

Given the reaction : CH3OH + 3/2 O2 --> CO2 + 2 H2O $\Delta H = -726.5 kJ$ In order to find the enthalpy change for the reverse reaction, we must multiply the enthalpy by -1 Therefore, the enthalpy would be $\Delta H = -726.5 * -1 = 726.5 kJ$

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