Answer
60.6 Joules
Work Step by Step
The dissolution of AgCl in water would be the reverse of the reaction shown so we must multiply the $\Delta H$ by negative 1 as follows;
AgCl --> Ag+ + Cl- $\Delta H$ = 65.5 kJ
This means one mole of AgCl dissolving into its constituent ions has a $\Delta H $ of 65.5kJ so then 9.25 x 10^-4 mol would release 9.25 x 10^-4 * 65.5kJ = 0.0606 kJ or 60.6 Joules
