## Chemistry: The Central Science (13th Edition)

About 38.0435ml of $HClO_4$.
1. Write and balance the equation: $HClO_4 + NaOH -> H_2O + NaClO_4$ $1 HClO_4 + 1 NaOH -> 1 H_2O + 1 NaClO_4$ 2. Now we can use this formula to find the volume. $C_1 * V_1 = C_2 * V_2$ $0.115 * V_1 = 0.0875 * 50$ $V_1 = \frac{4.375}{0.115}$ $V_1 \approx 38.0435ml$