## Chemistry: The Central Science (13th Edition)

$HCl + AgNO_3 -> AgCl + HNO_3$ 1. Because the proportion is 1:1, the number of moles of $HCl$ has to be the same of $AgNO_3$: nº of moles($HCl$) = nº of moles($AgNO_3$) 2. We can find the number of moles by this formula: $n = Concentration \times Volume$ $C(HCl) \times V(HCl) = C(AgNO_3) \times V(AgNO_3)$ $0.150 \times V(HCl) = 0.200 \times 0.015$ $V(HCl) = \frac{0.003}{0.15}$ $V(HCl) = 0.02L = 20ml$