Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 4 - Reactions in Aqueous Solution - Exercises - Page 160: 4.79a



Work Step by Step

$HCl + AgNO_3 -> AgCl + HNO_3$ 1. Because the proportion is 1:1, the number of moles of $HCl$ has to be the same of $AgNO_3$: nº of moles($HCl$) = nº of moles($AgNO_3$) 2. We can find the number of moles by this formula: $n = Concentration \times Volume$ $C(HCl) \times V(HCl) = C(AgNO_3) \times V(AgNO_3)$ $0.150 \times V(HCl) = 0.200 \times 0.015$ $V(HCl) = \frac{0.003}{0.15}$ $V(HCl) = 0.02L = 20ml$
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