## Chemistry: The Central Science (13th Edition)

This solution have 0.0168 Mol of $KBr_{}$.
1. Find the quantity of KBr Mols in 150ml of the solution using proportion calculations. $\frac{0,112 Mol}{x}$ = $\frac{1000ml}{150ml}$ 1000x = 16.8 x = 0.0168