Answer
Approximately 1.399M.
Work Step by Step
1. Find the mass of acetic acid:
$d = \frac{m}{v}$
$1.049 = \frac{m}{20}$
$m = 20 \times 1.049 = 20.98g$
2. Find the nº of moles:
Acetic acid: $CH_3COOH$
Molar Mass = $12 \times 2 + 1 \times 4 + 16 \times 2 = 60g/mol$
$mm = \frac{mass}{nºmoles}$
$60 = \frac{20.98}{nºmoles}$
$nºmoles = \frac{20.98}{60}$
$nºmoles \approx 0.349667$
3. Calculate the concentration:
$C = \frac{mol}{L}$
$C = \frac{0.349667}{0.25}$
$C \approx 1.399M$
