## Chemistry: The Central Science (13th Edition)

1. Find the mass of acetic acid: $d = \frac{m}{v}$ $1.049 = \frac{m}{20}$ $m = 20 \times 1.049 = 20.98g$ 2. Find the nº of moles: Acetic acid: $CH_3COOH$ Molar Mass = $12 \times 2 + 1 \times 4 + 16 \times 2 = 60g/mol$ $mm = \frac{mass}{nºmoles}$ $60 = \frac{20.98}{nºmoles}$ $nºmoles = \frac{20.98}{60}$ $nºmoles \approx 0.349667$ 3. Calculate the concentration: $C = \frac{mol}{L}$ $C = \frac{0.349667}{0.25}$ $C \approx 1.399M$