$KI$ $0.25M$ has a higher concentration of $ I^-$.
Work Step by Step
$BaI_2$ $0.10M:$ $[I^-] = 2 \times [BaI_2]$ $[I^-] = 0.20M$ $KI$ $0.25M:$ $[I^-] = 1 \times [KI]$ $[I^-] = 0.25M$
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