Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.46c



Work Step by Step

Since we are given percents, we assume a 100g basis to make the masses easy to calculate. Then we have 87.5g N and 12.5g H Now we need these in moles: N is 14g/mol so 87.5g is 6.25 moles H is 1g/mol so 12.5g is 12.5 moles Then we divide both by the smaller number to find the ratio 6.25/6.25 = 1 12.5/6.25 =2 The ratio is 1:2 so we have NH2
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