Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises - Page 115: 3.40d


There are $3.69 \times 10^{19} $ hydrogen atoms in 1.00 mg of aspartame.

Work Step by Step

1. As we have calculated in 3.40c, there are $2.05 \times 10^{18}$ aspartame molecules in 1.00 mg of that substance. We need to convert: number of aspartame molecules to number of hydrogen atoms. According to the molecular formula: $C_{14}H_{18}N_2O_5$, each aspartame molecule has 18 hydrogen atoms. Thus, the conversion factor is: $\frac{18 \space hydrogen \space atoms}{1 \space aspartame \space molecule }$ 2. Calculate the amount of hydrogen atoms: $2.05 \times 10^{18} \space aspartame \space molecules \times \frac{18 \space hydrogen \space atoms}{1 \space aspartame \space molecule} = $ $3.69 \times 10^{19} \space hydrogen \space atoms$
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