Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Exercises: 3.37a

Answer

3.725 x $10^{-1}$ g.

Work Step by Step

1. Find the molar mass of Ammonium Phosphate $(N_{}H_{4})_{3}P_{}O_{4}$. N: 14 x 3 = 42 H: 1 x 12 = 12 P: 31 x 1 = 31 O: 16 x 4 = 64 42 + 12 +31 + 64 = 149g/mol 2. Multiply the number of mols by the molar mass of the molecule: 2.5 x $10^{-3}$ x 149 = 372.5 x $10^{-3}$ = 3.725 $10^{-1}$g.
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