## Chemistry: The Central Science (13th Edition)

$3.40 \times 10^{-6} \space mole$ of aspartame.
1. Identify the conversion factors: - $mg$ to grams : $\frac{1 \space g}{1000 \space mg}$ - Grams (aspartame) to moles (aspartame): $\frac{1 \space mole \space (aspartame)}{294.3 \space g \space (aspartame)**}$ ** This was calculated in 3.40a 2. Calculate the number of moles in 1.00 mg of that substance. $1.00 \space mg \space (aspartame) \times \frac{1 \space g}{1000 \space mg} \times \frac{1 \space mole \space (aspartame)}{294.3 \space g \space (aspartame) }=$ $3.40 \times 10^{-6} \space mole \space (aspartame)$