## Chemistry: The Central Science (13th Edition)

There are $1.85 \times 10^{19}$ allicin molecules in 5.00 mg of that substance.
1. Identify the conversion factor: - Mole to molecules: $\frac{6.022 \times 10^{23} \space molecules}{1 \space mole}$ 2. As we have calculated in 3.39b, there is a total of $3.08 \times 10^{-5} \space mole$ of allicin in 5.00 mg of that substance. $3.08 \times 10^{-5} \space mole \times \frac{6.022 \times 10^{23} \space molecules}{1 \space mole} = 1.85 \times 10^{19} \space molecules$