Answer
Dichloroethylenediamminecadmium(II)
Work Step by Step
1. $[Cd(en)Cl_{2}]$ is a complex. $Cd$ is a metal with two different ligands attached $(en)$ and $Cl_{2}$
2. Ligands are named first then is the metal. Prefixes are added and Ligands are alphabetically named. $Cl_{2}$ is dichloro and $en$ is ethylenediamine.
3. Cd is cadmium.
4. In order to find the oxidation number on the metal, we add the charges and equal it to the charge on the complex, in this case zero. $en$ has no charge and chloride is $ 2\times(-1)$
Thus,
$x+0+2\times (-1)=0$
$x-2=0$
$x=+2$
The charge is +2 on the metal. Hence, the name of the complex is dichloroethylenediamminecadmium(II)
