Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 23 - Transition Metals and Coordination Chemistry - Exercises - Page 1034: 23.38b


Potassium hexacyanomanganate(II)

Work Step by Step

1. In $K_{4}[Mn(CN)_{6}]$, $K_{4}$ is the cation whereas $[Mn(CN)_{6}]$ is the anion. Cations are named first then are anions. When the complex is the anion, its name has -ate at the end. 2. In order to name the anion, Ligand is named first then is the metal. Thus, since six Cyanide ions are present: hexacyano 3. Mn is Manganese but since the complex is an anion, its named as Manganate. 4. In order to write the charge on the metal, we add the charges and equal it to the charge on the complex, in this case zero. Potassium has +1 charge and cyanide has a -1 charge. Thus, $4\times (+1) +x +6 (-1) =0$ $+4+x-6=0$ $x=+6-4$ $x=+2$ Thus the charge is +2 on the metal. Hence, the name of the complex is Potassium hexacyanomanganate (II)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.