Answer
Potassium hexachlorotitanate(IV)
Work Step by Step
1. In $K_{2}[TiCl_{6}]$ , $K_{2}$ is the cation whereas $[TiCl_{6}]$ is the anion. Cations are named first then are anions. When the complex is the anion, its name has an -ate at the end.
2. In order to name the anion, Ligand is named first then is the metal. Thus, since six chloride ions are present: hexachloro.
3. Ti is titanium metal but since the complex is an anion, it is titanate.
4. In order to find the charge on the metal, we add the charges and equal it to the charge on the complex, in this case zero. Thus,
$+2 +x + 6\times (-1) =0$
$+2+x-6=0$
$x=+6-2$
$x= 4$
Thus the charge is +4 on the metal. Hence, the name of the complex is potassium hexachlorotitanate(IV)
