Answer
pentamminecarbonatochromium(III) chloride.
Work Step by Step
1. In $[Cr(NH_{3})_{5}(CO_{3})]Cl$, $[Cr(NH_{3})_{5}(CO_{3})]$ is the cation whereas $Cl$ is the anion. Cations are named first, then are anions.
2. In this complex, Cr is bonded to two different ligands $(NH_{3})_{5}$ and $CO_{3}$. The ligands are named first then is the metal. Prefixes are added and ligands are named alphabetically. $(NH_{3})_{5}$ is pentammine whereas $CO_{3}$ is carbonato.
3. $Cr$ is chromium.
4. In order to find the oxidation number on the metal, we add the charges and equal it to the charge on the complex, in this case zero. $NH_{3}$ has no charge, $CO_{3}$ has a -2 charge and $Cl$ has -1 charge. Thus,
$x-2-1=0$
$x-3=0$
$x=+3$
Pentamminecarbonatochromium(III) chloride.
