Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 23 - Transition Metals and Coordination Chemistry - Exercises - Page 1034: 23.35a

Answer

$[Cr(NH_{3})_{6}](NO_{3})_{3}$

Work Step by Step

The formula is written according to the rules of writing the formula for complex compounds. 1. Hexaamminechromium(III) is a cation whereas nitrate is the anion. Cations are written first then anion. 2. Hexaammine is the ligand and chromium is the metal. Thus, $[Cr(NH_{3})_{6}]$ 3. Chromium(III) means the oxidation state of chromium ion is +3. $NH_{3}$ is a molecule so the oxidation state is zero. 4. Nitrate $NO_{3}^{-}$ has a -1 charge. In order to balance the charge on the cation and anion, 3 atoms of nitrate ion should be present. Therefore the chemical formula is: $[Cr(NH_{3})_{6}](NO_{3})_{3}$
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