Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Exercises - Page 770: 17.53a

Answer

$K_{ps} = 7.626 \times 10^{-9}$

Work Step by Step

1. Write the Kps formula: $K_{ps} = [Ca^{2+}]*[F^-]^2$ $[Ca^{2+}] = 1.24 \times 10^{-3}M$ $[F^-] = 2 * 1.24 \times 10^{-3} = 2.48 \times 10^{-3}M$ 2. Calculate the Kps: $K_{ps} = [1.24 \times 10^{-3}] * [2.48 \times 10^{-3}]^2 $ $K_{ps} = [1.24 \times 10^{-3}] * [6.1504 \times 10^{-6}] $ $K_{ps} = 7.626 \times 10^{-9}$
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