## Chemistry: The Central Science (13th Edition)

$K_{ps} = 7.626 \times 10^{-9}$
1. Write the Kps formula: $K_{ps} = [Ca^{2+}]*[F^-]^2$ $[Ca^{2+}] = 1.24 \times 10^{-3}M$ $[F^-] = 2 * 1.24 \times 10^{-3} = 2.48 \times 10^{-3}M$ 2. Calculate the Kps: $K_{ps} = [1.24 \times 10^{-3}] * [2.48 \times 10^{-3}]^2$ $K_{ps} = [1.24 \times 10^{-3}] * [6.1504 \times 10^{-6}]$ $K_{ps} = 7.626 \times 10^{-9}$