Answer
$K_{ps} = 4 \times 10^{-6} $
Work Step by Step
1. Write the Kps formula:
$K_{ps} = [Pb^{2+}]*[Br^-]^2$
2. Find the Kps value:
$[PbBr_2]= 1 \times 10^{-2} M$
$[Pb^{2+}] = 1 * ( 1 \times 10^{-2}) = 1 \times 10^{-2} M$
$[Br^-] = 2 *( 1 \times 10^{-2}) M = 2 \times 10^{-2} M$
$K_{ps} = [ 1 \times 10^{-2}] * [2 \times 10^{-2}]^2$
$K_{ps} = 1 \times 10^{-2} * 4 \times 10^{-4} $
$K_{ps} = 4 \times 10^{-6} $
