## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 3 - Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 149e: 70c

#### Answer

The theoretical mass is equal to $85.2g (CH_3OH)$.

#### Work Step by Step

1. Calculate the number of moles of $CO$: 12.01* 1 + 16* 1 = 28.01g/mol $74.5g \times \frac{1 mol}{ 28.01g} = 2.66mol (CO)$ - The balanced reaction is: $CO + 2H_2 -- \gt CH_3OH$ The ratio of $CO$ to $CH_3OH$ is 1 to 1: $2.66 mol (CO) \times \frac{ 1 mol(CH_3OH)}{ 1 mol (CO)} = 2.66mol (CH_3OH)$ 2. Calculate the mass of $CH_3OH$: 12.01* 1 + 1.01* 3 + 16* 1 + 1.01* 1 = 32.05g/mol $2.66 mol \times \frac{ 32.05 g}{ 1 mol} = 85.2g (CH_3OH)$

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