The balanced equation for this reaction is: $NH_4NO_3 \lt -- \gt N_2O + 2H_2O$
Work Step by Step
Ammonium nitrate: $NH_4NO_3$ Dinitrogen monoxide: $N_2O$ Water : $H_2O$ Therefore, this is the unbalanced reaction: $NH_4NO_3 \lt -- \gt N_2O + H_2O$ Let's start by balancing the compounds that only appear in 1 compound on each side. Nitrogen: Products = 2, Reactants = 2: Balanced. Hydrogen: Products = 2, Reactants = 4: Unbalanced. To correct this, we have to put 2 as the coefficient of water: $NH_4NO_3 \lt -- \gt N_2O + 2H_2O$ Oxygen: Products: 2*1 + 1 = 3, Reactants = 3: This is balanced.