## Chemistry: The Molecular Science (5th Edition)

$CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + 4CO_2 + 2NaCl + 2NaF$
1. Write the unbalanced reaction, based on the reactants and products described in the exercise: $CCl_2F_2 + Na_2C_2O_4 -- \gt C + CO_2 + NaCl + NaF$ 2. Let's start by giving the coefficients of the chlorine and fluorine compounds: $1CCl_2F_2 + Na_2C_2O_4 -- \gt C + CO_2 + 2NaCl + 2NaF$ 3. Now, we have a total of 4 sodiums on the products side, so we have to put a 2 on the sodium oxalate: $1CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + CO_2 + 2NaCl + 2NaF$ 4. We have 8 oxygens on the reactant's side, so we have to put a 4 on the carbon dioxide. $1CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + 4CO_2 + 2NaCl + 2NaF$ Now, the reaction is totally balanced.