Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 3 - Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 149e: 67b

Answer

526g of carbon monoxide.

Work Step by Step

1. Calculate the number of moles of $Fe_2O_3$: 55.85* 2 + 16* 3 = 159.7g/mol $1000g \times \frac{1 mol}{ 159.7g} = 6.262mol (Fe_2O_3)$ The ratio of $Fe_2O_3$ to $CO$ is 1 to 3: $6.262 mol (Fe_2O_3) \times \frac{ 3 mol(CO)}{ 1 mol (Fe_2O_3)} = 18.79mol (CO)$ 2. Calculate the mass of $CO$: 12.01* 1 + 16* 1 = 28.01g/mol $18.79 mol \times \frac{ 28.01 g}{ 1 mol} = 526g (CO)$
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