Chemistry: The Molecular Science (5th Edition)

We can obtain 699g of $Fe$ using 1 kg of $Fe_2O_3$
1. Calculate the number of moles of $Fe_2O_3$: 55.85* 2 + 16* 3 = 159.7g/mol $1000g \times \frac{1 mol}{ 159.7g} = 6.26mol (Fe_2O_3)$ The ratio of $Fe_2O_3$ to $Fe$ is 1 to 2 (According to the reaction of the question): $6.26 mol (Fe_2O_3) \times \frac{ 2 mol(Fe)}{ 1 mol (Fe_2O_3)} = 12.52mol (Fe)$ 2. Calculate the mass of $Fe$: 55.85* 1 = 55.85g/mol $12.52 mol \times \frac{ 55.85 g}{ 1 mol} = 699g (Fe)$